Hypothesis:
Conservation of energy will only apply in elastic collisions.
Data/Analysis:
KE = 1/2mv^2
P = mv
Cup 1
KE = 1/2 (.515)(.67)^2 = .12 J
P = (.515)(.67) = .34kg*m/s
Cup 2
KE = .08 J
P = .29 kg*m/s
% change = 66%
Cup 1
Before:
KE = .08 J
P = .28 kg*m/s
After:
KE = .01 J
P = .10 kg*m/s
Cup 2
KE = .01 J
P = .10 kg*m/s
% change = 12.5%
Cup 1
KE =.21 J
P = .66 kgm/s
Cup 2
KE =..08 J
P = .29 kgm/s
% change = 38%
Cup 1
Before:
KE = .15 J
P =.55 kgm/s
After:
KE = .04 J
P = .3 kgm/s
Cup 2
KE = .02 J
P = .15 kgm/s
Hypothesis:
Conservation of energy will only apply in elastic collisions.
Data/Analysis:
KE = 1/2mv^2
P = mv
Cup 1
KE = 1/2 (.515)(.67)^2 = .12 J
P = (.515)(.67) = .34kg*m/s
Cup 2
KE = .08 J
P = .29 kg*m/s
% change = 66%
Cup 1
Before:
KE = .08 J
P = .28 kg*m/s
After:
KE = .01 J
P = .10 kg*m/s
Cup 2
KE = .01 J
P = .10 kg*m/s
% change = 12.5%
Cup 1
KE =.21 J
P = .66 kgm/s
Cup 2
KE =..08 J
P = .29 kgm/s
% change = 38%
Cup 1
Before:
KE = .15 J
P =.55 kgm/s
After:
KE = .04 J
P = .3 kgm/s
Cup 2
KE = .02 J
P = .15 kgm/s
% Change = 26%, 13%